![Can anybody please explain why console.log works in first one but doesn't work in second one ? : r/learnjavascript Can anybody please explain why console.log works in first one but doesn't work in second one ? : r/learnjavascript](https://preview.redd.it/can-anybody-please-explain-why-works-in-first-one-but-v0-opudf90lz37b1.jpg?width=640&crop=smart&auto=webp&s=44742625415ada436c3b1a979a5a84d5db89554a)
Can anybody please explain why console.log works in first one but doesn't work in second one ? : r/learnjavascript
![JavaScript Frontend Interview Question: console.log(3 + + "3") — Can You Solve These Mind-Bending Console Mysteries? | by Harshit Raj | Medium JavaScript Frontend Interview Question: console.log(3 + + "3") — Can You Solve These Mind-Bending Console Mysteries? | by Harshit Raj | Medium](https://miro.medium.com/v2/resize:fit:1400/1*SsdLOqzX2AYBK4N4ftr7Ng.png)
JavaScript Frontend Interview Question: console.log(3 + + "3") — Can You Solve These Mind-Bending Console Mysteries? | by Harshit Raj | Medium
![javascript - How do I restore console.log() function that has been disabled by a website? - Stack Overflow javascript - How do I restore console.log() function that has been disabled by a website? - Stack Overflow](https://i.stack.imgur.com/1QcRL.png)
javascript - How do I restore console.log() function that has been disabled by a website? - Stack Overflow
![When the user done typing event is called, it calls the function donetype. However, it console logs 'Done Typing', but it doesn't remove the appended element with the class of .usertyping. Any When the user done typing event is called, it calls the function donetype. However, it console logs 'Done Typing', but it doesn't remove the appended element with the class of .usertyping. Any](https://imgur.com/ZLqT7Rx.png)
When the user done typing event is called, it calls the function donetype. However, it console logs 'Done Typing', but it doesn't remove the appended element with the class of .usertyping. Any
![codedamn on X: "- Console Logging One of the simplest ways to debug JavaScript code is by using the console.log() function. This function logs a message to the console, which can be codedamn on X: "- Console Logging One of the simplest ways to debug JavaScript code is by using the console.log() function. This function logs a message to the console, which can be](https://pbs.twimg.com/media/FsNnCDUXwAE5JOY.png)